0=x^2+x+40

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Solution for 0=x^2+x+40 equation: 



0=x^2+x+40

We move all terms to the left:

0-(x^2+x+40)=0

We add all the numbers together, and all the variables

-(x^2+x+40)=0

We get rid of parentheses

-x^2-x-40=0

We add all the numbers together, and all the variables

-1x^2-1x-40=0

a = -1; b = -1; c = -40;
Δ = b2-4ac
Δ = -12-4·(-1)·(-40)
Δ = -159
Delta is less than zero, so there is no solution for the equation

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